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Scian 2021. 8. 10. 18:13
๋ฐ˜์‘ํ˜•

$a_{n+1}=pa_n+q$ ๊ผด์˜ ์ˆ˜์—ด (pqํ˜• ์ ํ™”์‹(๊ด€๊ณ„์‹))

* ๊ด€๊ณ„์‹์ด ์ž˜ ์•ˆ๋ณด์ž„

 

[๋ณ€ํ˜• ๋ฐฉ๋ฒ• ์™ธ์šฐ๊ธฐ]

$a_{n+1}-\alpha =p(a_n-\alpha )$

$a_{n+1} =p(a_n-p\alpha +\alpha)$

โ–ถ $q=-p\alpha +\alpha $

$\alpha=p\alpha +q$ ($a_{n+1}=pa_n+q$ ๊ผด๊ณผ ๋น„์Šท)

 

๋„์›€์ด ๋ ๋งŒํ•œ ์ž๋ฃŒ

https://m.blog.naver.com/ao9364/221651296608

 

์ˆ˜์—ด์˜ ์ ํ™”์‹์˜ ๊ธฐ์ดˆ ํ•ด๋ฒ•๊ณผ ํŠน์„ฑ๋ฐฉ์ •์‹ ์ดํ•ดํ•˜๊ธฐ

๋“ค์–ด๊ฐ€๊ธฐ... ์ ํ™”์‹์„ ์ง์ ‘ ํ’€์–ด๋‚ด๋Š” ๋ฐฉ๋ฒ•์€ ์‚ฌ์‹ค ๊ต์œก๊ณผ์ •์—์„œ ๋น ์ง„์ง€ ์ข€ ์˜ค๋ž˜๋˜์—ˆ์ฃ ... ๋ฌผ๋ก  ๊ณ ๋“ฑํ•™๊ต ๋ชจ...

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๋ถ„์ˆ˜ ๊ผด์˜ ๊ด€๊ณ„์‹

: ์—ญ์ˆ˜ ์ทจํ•ด์„œ(๋’ค์ง‘์–ด์„œ) ๊ณ„์‚ฐ ํ›„ $\frac{1}{a_n}$์„ $b_n$์œผ๋กœ ์น˜ํ™˜ํ•˜์—ฌ ํ’€์ด!


$a_n$๊ณผ $S_n$ ์‚ฌ์ด์˜ ๊ด€๊ณ„์‹์ด ์ฃผ์–ด์ง„ ์ˆ˜์—ด

Step 1.

$S_{n+1}-S_n=a_{n+1}$ ์‹ ์ด์šฉ

 

Step 2.

n → n+1๋กœ ๋Œ€์ž…ํ•˜์—ฌ ๋‚˜์˜จ ์‹($S_{n+1}$)๊ณผ $S_n$์„ Step 1์˜ ๊ด€๊ณ„๋ฅผ ์ด์šฉํ•˜์—ฌ $a_n$ ๋˜๋Š” $S_n$๋งŒ ๋‚จ๋„๋ก ํ•œ๋‹ค.

๋ฐ˜์‘ํ˜•